<?php

$con=mysqli_connect("localhost","数据库用户名","数据库用户密码","数据库名");

// 检测连接

if (mysqli_connect_errno()) {

    echo "连接失败: " . mysqli_connect_error();

}

//根据表id修改指定的内容

mysqli_query($con,"UPDATE hy_user SET name='这里是修改的内容'

WHERE id='1'");

//关闭之前打开数据库

mysqli_close($con);

?>